Lista 1 L12 = L23 L12 = 0 Resposta em módulo q1/q2 = 4 q1/q2 = -4 q2 q1 + 1,0 μC q2 = -3,0 μC L = 10 cm F13 = F23 K.q1.q3/x = K.q2.q3/(x + L)^2 1/x = 3/(x + 10)^2 1/x = √3/(x + L) x + L = √3x x + 10 = √3x 10 = √3x - x 10 = x(√3 - 1) x = 10/(√3 - 1) x = 13,06 cm x = -13,6 cm = -13,7 cm Está sobre o eixo X, portanto y = 0 Lista 2 EP = 0 d = 3R q1/q2 K.q1.R/(R + R^2)^3/2 K.q2.R/(2R + R^2)^3/2 q1/q2 = 2.9/(2R^2)^3/2 q1/q2 = 29/√3.2R^3 → q1/q2 = 29√5/3 q1/q2 = 4√2/5√5 = 0,506 Teorema Pitágoras -9 = -3,20 x 10^-19C +9 = 3,20 x 10^-19C Ponto P1, y = H m Eqx - Eqy = 0 ET = 2.Eqx ET = 2.senθ.9.10^9.3.20x10^-19/25 ET = 2.3/5.9.10^9.3.20x10^-19/25 ET = 1,38.10^-10 N/C senθ = 3/5 cosθ = 4/5 Lista 3 L3 = 3,2 mm = 0,0032 m E = 1800 N/C Normal ϕ = E.A.cosβ = 1800.0,0032.0,0032.cos145º ϕ = 0,018432.cos145º ϕ = -0,015 N.m^2/C E = 3,0 mm N/C ϕ = E.A.cosβ ϕ = 3.10^-3.3,1416.0,11.0,11.cos180º A = π.r^2 A = 3,1416.0,11.0,11 ϕ = 0,1140 = 1,14.10^-4 N.m^2/C
